24h^2-12h=26

Solution for 24h^2-12h=26 equation:

24h^2-12h=26

We move all terms to the left:

24h^2-12h-(26)=0

a = 24; b = -12; c = -26;
Δ = b2-4ac
Δ = -122-4·24·(-26)
Δ = 2640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2640}=\sqrt{16*165}=\sqrt{16}*\sqrt{165}=4\sqrt{165}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{165}}{2*24}=\frac{12-4\sqrt{165}}{48}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{165}}{2*24}=\frac{12+4\sqrt{165}}{48}
$